noobtv.blogg.se - Java code

#JAVA CODE HOW TO#

The letter E is in the secret word! There are 1 E 's in the word. The letter L is in the secret word! There are 1 L 's in the word. The letter A is in the secret word! There are 1 A 's in the word. The letter P is in the secret word! There are 2 P 's in the word. Output of code: Enter the word for guesser: ("You guessed the entire word " + wordToGuess.toUpperCase() + " correctly! It took you " + chances + " attempts!") ("The letter " + currentGuessChar + " is in the secret word! There are " + times + " " + currentGuessChar + " 's in the word. If (wordToGuessChars = currentGuessChar)Ĭensor = currentGuessChar //replaces _ with guessed letter in caps Int times = 0 //number of times a letter is in the word if the guess is not a duplicated guess, it checks if the guessed letter is in the word (prevGuesses.stream().reduce("", String::concat))

("You already guessed this letter! Try again. If (ntains(currentGuess)) //checks if user already guessed the letter previously String currentGuess = input.next().toUpperCase().substring(0, 1) Ĭhar currentGuessChar = currentGuess.charAt(0) //gets char data from scanner (censor) //prints the censored secret word While (!String.valueOf(censor).equals(wordToGuess))īoolean correct = false //lets the user know if the letter is in the word or notīoolean repeated = false //check if user guessed the same letter twice ("Your secret word is: ") // prints an array of chars with the same length as stringįor (int index = 0 index < length index++) String wordToGuess = input.nextLine().toUpperCase() Ĭhar wordToGuessChars = wordToGuess.toCharArray() //creates character array of stringsĬhar censor = wordToGuess.toCharArray()

On guessing the word successfully, the program will show the number of attempts at the end.

If the user already guessed the letter before, the program will tell the user of that and show their previous guesses without repeating any letters.

It will also show the progress of the censored word after each guess.

The program will tell the guesser if their guessed letter is in the word or not.

The word will be censored by the program.

The game will first ask the user to type a word that the 2nd person/guesser will then guess.

Also, while guessing the word, if a guessed letter is not in the word, it is written separately on the side, so that the guesser does not waste a chance on the same word again.

And for every wrong guess, the lives reduce and the guesser can run out of lives, hence losing the game.

Once the guesser is coming close to guessing the word, he can attempt to guess the whole word and if he guesses it right, he/she has won the game.

However,if the guessed letter does not occur in the word, the guesser loses a life and has lesser chances to guess the word currently.

Once the guesser says an alphabet, if the word contains that letter and is guessed right, the other player will write it in all the correct positions of the word to be guessed.

The second player/guesser now has to guess the word and has limited chances or lives to do so.

The word is then displayed as XXXX with the number of Xs equal to the length of the guessed word.The first player thinks of a word which ideally should be a noun like a name of a place,animal,thing etc, but should make sure it is not a Name of a person, or any slang or informal words.Hence, the following rules explain how Hangman is played: Overview of Hangman game in Java:įirstly, we should know what kind of game Hangman is and how do we play it.

#JAVA CODE HOW TO#

So let’s start learning how to create a hangman game in Java. In this Java Program, we implement the popular game Hangman in Java.